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4.904x^2-120x-150=0
a = 4.904; b = -120; c = -150;
Δ = b2-4ac
Δ = -1202-4·4.904·(-150)
Δ = 17342.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-\sqrt{17342.4}}{2*4.904}=\frac{120-\sqrt{17342.4}}{9.808} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+\sqrt{17342.4}}{2*4.904}=\frac{120+\sqrt{17342.4}}{9.808} $
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